Question

已知:A=-2^5,B=2^5,求A^2-2AB+B^2和A^3-3A^2B+3AB^2-B^3

Answer 1

A^2-2AB+B^2

=(A-B)^2=(-2*2^5)^2=(2^6)^2=2^12

A^3-3A^2B+3AB^2-B^3

=(A-B)^3=(-2*2^5)^3=(-2^6)^3=-2^18