Question

矩形ABCD的对角线AC,BD相交与点O,点E,F分别在OA,OD上,且AE=DF

Answer 1

在矩形ABCD中,有AB=DC,AO=DO,∠BAE=∠CDF,AD‖BC,AO=DO,AE=DF作EG//AD交OD于G,则 ,∠OEG=∠OAD,∠OGE＝∠ODA所以 ∠OEG=∠OGE所以 OE=OG,AE=DG又 AE=DF,所以 DG=DF,所以 F与G重合∴EF‖AD‖BC∴四边形EBCF是梯形AB=D...