lim(n->∞)[2^(2n-1)+1]/(4^n-3^n)=?
1个回答
=lim[1/2*4^n+1]/[4^n-3^n]
=lim[1/2+1/4^n]/[1-(3/4)^n]
=1/2
相关问题
lim(n→∞)[3n²+4n-2/(2n+1)²]
求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)
lim(1/n2+2/n2+3/n2+……n/n2)为什么不等于lim1/n2 +lim2/n2 +lim3/n2……+
求下列极限~(大一级别)1.lim(n→∞)3n^2+n+1/n^3+4n^2-12.lim(n→∞)(1/n^2+2/
n→∞ lim[1+1/(1+2n)+1/(2+2n)+1/(3+2n)+1/(4+2n).+1/(n+2n)]=
求下列极限:(1)lim 3n^2-2n+1/8-n^3 n→∞ (2)lim 1+2+3+…+n/n^2 n→∞
lim(n->无穷)(1/4n^2-2^2+2/4n^2-3^2+...+n-1/4n^2-n^2)
lim(1/n^2+4/n^2+7/n^2+……+(3n-2)/n^2)
一.lim(2/3)^n=?二.lim(3^n+1)/[3^(n+1)+2^n]=?
lim2^n-3^n/2^n+1+3^n+1