(x2+3x+12)(x2+7x+12)-120

1个回答

  • 如果是12的话就没有办法分解了,对不起

    (X^2+3x+2)(x^2+7x+12)-120

    =(x+1)(x+2)(x+3)(x+4)-120

    =(X^2+5x+4)(x^2+5x+6)-120

    =(X^2+5x+4)^2+2(X^2+5x+4)-120

    =(X^2+5x+4+12)(X^2+5x+4-10)

    =(X^2+5x+16)(X^2+5x-6)

    =(x-1)(x+6)(X^2+5x+16)