100x²-200x+81y²+162y=7919
(100x²-200x+100)+(81y²+162y+81)=7919+100+81
100(x²-2x+1)+81(y²+2y+1)=8100
100(x-1)²+81(y+1)²=8100
两边同时除以8100,得:
(x-1)²/81+(y+1)²/100=1
即:(x-1)²/9²+(y+1)²/10²=1
100x²-200x+81y²+162y=7919
(100x²-200x+100)+(81y²+162y+81)=7919+100+81
100(x²-2x+1)+81(y²+2y+1)=8100
100(x-1)²+81(y+1)²=8100
两边同时除以8100,得:
(x-1)²/81+(y+1)²/100=1
即:(x-1)²/9²+(y+1)²/10²=1