Question

已知tan(3x+π/4)=根号3,x属于[0,2π],求符合条件的角的集合

Answer 1

tan(3x+π/4)=根号3,

3x+π/4=kπ+π/6

x=kπ/3-π/36,k∈Z

x属于[0,2π],

k=1,2,3,4,5,6

符合条件的角的集合:

{x|x=kπ/3-π/36,k=1,2,3,4,5,6}