∵a2-16b2-c2+6ab+10bc=a2+9b2+6ab-25b2-c2+10bc=(a+3b)2-(c-5b)2=0,
∴(a+3b+c-5b)(a+3b-c+5b)=0,
即(a+c-2b)(a-c+8b)=0,
∴a+c-2b=0或a-c+8b=0,
∴a+c=2b或a+8b=c,
∵a+b>c,
∴a+8b=c不符合题意,舍去,
∴a+c=2b.
∵a2-16b2-c2+6ab+10bc=a2+9b2+6ab-25b2-c2+10bc=(a+3b)2-(c-5b)2=0,
∴(a+3b+c-5b)(a+3b-c+5b)=0,
即(a+c-2b)(a-c+8b)=0,
∴a+c-2b=0或a-c+8b=0,
∴a+c=2b或a+8b=c,
∵a+b>c,
∴a+8b=c不符合题意,舍去,
∴a+c=2b.