(1)√3分之√27*√2-√8
=3√2-2√2
=√2
(2))√27-√3分之1+√12
=3√3-√3/3+2√3
=5√3-√3/3
=14√3/3
(3)(3+√5)的平方-(3-√5)的平方
=9+6√5+5-9+6√5-5
=12√5
(4)√3分之2√12+√3+(1-√3)的0次方
=4+√3+1
=5+√3
(1)√3分之√27*√2-√8
=3√2-2√2
=√2
(2))√27-√3分之1+√12
=3√3-√3/3+2√3
=5√3-√3/3
=14√3/3
(3)(3+√5)的平方-(3-√5)的平方
=9+6√5+5-9+6√5-5
=12√5
(4)√3分之2√12+√3+(1-√3)的0次方
=4+√3+1
=5+√3