Question

已知X平方+Y平方+4X+6Y+13=0,且x,y为实数,则y的x方为多少

Answer 1

X平方+Y平方+4X+6Y+13

=(x^2+4x+4)+(y^2+6y+9)

=(x+2)^2+(y+3)^2

=0

x+2=0,y+3=0

x=-2,y=-3

y^x=(-3)^(-2)=1/9