Question

用因式分解法解方程:(x^2-2x+2)(x^2-2x-4)+5=0.速速回答.

Answer 1

(x^2-2x+2)(x^2-2x-4)+5=0

(x^2-2x+2)[(x^2-2x+2)-6]+5=0

[(x^2-2x+2)-5][(x^2-2x+2)-1]=0

(x^2-2x-3)(x^2-2x+1)=0

(x-3)(x+1)(x-1)^2=0

x-3=0 或x+1=0或x-1=0

x=3或x=1或x=-1