(x^2+y^2)^2-4xy(x^2+y^2)+4x^2y^2
把x²+y²看作一个数；把2xy看作一个数；
原式=[（x²+y²）-2xy]²
=[（x-y)²]²
=[(-2/3)²]²
=16/81
已知x-y=-2/3 求(x^2+y^2)^2-4xy(x^2+y^2)+4x^2y^2
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