cosA=-√2/4,则:sinA=√14/4
a/sinA=c/sinC,
2/[√14/4]=[√2]/[sinC]
sinC=√7/4
cosC=3/4
cosB=-cos(A+C)=(10√2)/(16)=(5√2)/8
则:
b²=a²+c²-2accosB=4+2-5=1
则:b=1
cosA=-√2/4,则:sinA=√14/4
a/sinA=c/sinC,
2/[√14/4]=[√2]/[sinC]
sinC=√7/4
cosC=3/4
cosB=-cos(A+C)=(10√2)/(16)=(5√2)/8
则:
b²=a²+c²-2accosB=4+2-5=1
则:b=1