（4x^2-4xy+y^2）+(x^2-2x+1)=0
=>(2x-y)^2+(x-1)^2=0
x=1
y=2
(x-y)^2005=-1
1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.
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