Question

化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/

Answer 1

通分

原式={[a^(1/2)-b^(1/2)]^2+[a^(1/2)+b^(1/2)]^2/[a^(1/2)+b^(1/2)] [a^(1/2)-b^(1/2)]

=[a-2a^(1/2)b^(1/2)+b+a+2a^(1/2)b^(1/2)+b]/(a-b)

=(2a+2b)/(a-b)