1/√n=2/(√n+√n)>2/(√n+1+√n)=2(√n+1 -√n)
所以1+1/√2+1/√3+...+1/√n
>2(√2-1)+2(√3-√2)+2(√4-√3)+...+2(√n+1-√n)
=2(√n+1-1)
右边也一样,1/√n=2/(√n+√n)<2/(√n-1+√n)=2(√n -√n-1)
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1/√n=2/(√n+√n)>2/(√n+1+√n)=2(√n+1 -√n)
所以1+1/√2+1/√3+...+1/√n
>2(√2-1)+2(√3-√2)+2(√4-√3)+...+2(√n+1-√n)
=2(√n+1-1)
右边也一样,1/√n=2/(√n+√n)<2/(√n-1+√n)=2(√n -√n-1)
..