Question

已知【x+1】的2次方+y+2的绝对值=0，求代数式5xy-3分之2x的3次方y的2次方-4xy+2

Answer 1

x + 1 = 0 ==> x = -1

y + 2 = 0 ==> y = -2

5xy - (2/3)x^3y^2 - 4xy + 2

= 5 * (-1)*(-2) - (2/3)*(-1)^3 * (-2)^2 - 4 * (-1) * (-2) + 2

= 10 + (2/3) * 1 * 4 - 8 + 2

= 10 + 8/3 - 8 + 2

= 4 + 8/3

= 20/3