Question

已知直线y=kx+b过点A(2,0)及直线y=5X-3与y轴交点,那么这条直线的解析式为

Answer 1

y=5x-3,x=0,y=-3

y=kx+b过点：(2,0);(0,-3)

2k+b=0,b=-3

k=3/2,b=-3

y=3x/2-3