Question

计算log3[(9^2 * 27^(1/3))/3^(log3 234)]

Answer 1

[(9^2 * 27^(1/3))/3^(log3 234)]=(9^2 * 27^(1/3))/3^(log3 234)

=(81*3)/(234)

=3^5/234

log3[(9^2 * 27^(1/3))/3^(log3 234)]

=log3(3^5/234)

=5-log3(234)

另外这里是不是243啊 如果是243的话,那就等于

=5-log3(243)

=5-5=0