(1)
设P(m,n),m>0,n>0;
y=0,0=(1/2)x+1,x=-2;A(-2,0);
x=0,y=(1/2)*0+1=1;C(0,1);
AB=m-(-2)=m+2,
PB=n,
S△APB=AB*PB/2=4
(m+2)*n=8...(a)
又P在直线y=(1/2)x+1上,所以n=(1/2)m+1,代入(a):
(m+2)[(1/2)m+1]=8
(m+2)(m+2)=16
m+2=±4
m1=4-2=2;
m2=-4-2=-6
(1)
设P(m,n),m>0,n>0;
y=0,0=(1/2)x+1,x=-2;A(-2,0);
x=0,y=(1/2)*0+1=1;C(0,1);
AB=m-(-2)=m+2,
PB=n,
S△APB=AB*PB/2=4
(m+2)*n=8...(a)
又P在直线y=(1/2)x+1上,所以n=(1/2)m+1,代入(a):
(m+2)[(1/2)m+1]=8
(m+2)(m+2)=16
m+2=±4
m1=4-2=2;
m2=-4-2=-6