计算以下定积分,要求有具体过程,式子见图.

1个回答

∫［0,2］f(x) dx
=∫[0,1] x² dx+∫[1,2] x-1 dx
=x³/3 |[0,1] +x²/2 |[1,2]
=1/3 +3/2
=11/6