Question

已知（x+3)/2=(y+4)/3=(z+8)/4,且x+y+z＝60,求x、y、z的值

Answer 1

令（x+3)/2=(y+4)/3=(z+8)/4=k

则x+3=2k,x=2k-3

y+4=3k,y=3k-4

z+8=4k,z=4k-8

x+y+z=60

2k-3+3k-4+4k-8=60

9k=75

k=25/3

x=2k-3=41/3

y=3k-4=21

z=4k-8=76/3