Question

如果分式(3x-1)/(x-1)(x-2)=A/(x-1)+B/(x+2),那么A,B的值分别是什么

Answer 1

你题目抄错了,应该是(3x-1)/(x-1)(x-2)=A/(x-1)+B/(x-2)

因为 A/(x-1)+B/(x-2)＝(Ax-2A+Bx-B)/(x-1)(x-2)

＝[(A+B)x-(2A+B)]/(x-1)(x-2)

＝(3x-1)/(x-1)(x-2)

根据对应系数分别相等

所以,A+B=3

2A+B=1

解得,A=-2,B=5

选,A .-2,5