Question

若(k+m)x+4=0和(2k-m)x-1=0是关于x的同解方程,则k/m-2的值是

Answer 1

由(k+m)x+4=0

(2k-m)x-1=0

得(k+m)x=-4和(2k-m)x=1

然后相除,得(k+m)/(2k-m)=-4

化得9k=3m

k/m-2=-5/3