Question

sin(540°+α)cos(360°-α)/sin(450°+α)tan(900°-α)

Answer 1

sin(540°+α)cos(360°-α)/[sin(450°+α)tan(900°-α)]

=sin(180°+α)cosα/[sin(90°+α)tan(180°-α)]

=-sinαcosα/[-cosα.tanα]

=-sinαcosα/[-sinα]

=cosα