√12+√3/2 =2√3+√3/2=5√3/2
[ 2/(a+1)+(a+2)/a^-1] ÷[a/(a+1)]
= [2/(a+1)+ a(a+2)]*(a+1)/a
= [2+a(a+1)(a+2)]/a
= 2/a + (a+1)(a+2)
= 2/(√3+1) + (√3+2)(√3+3)
= (√3-1) + 9 + 5√3
= 8+6√3
√12+√3/2 =2√3+√3/2=5√3/2
[ 2/(a+1)+(a+2)/a^-1] ÷[a/(a+1)]
= [2/(a+1)+ a(a+2)]*(a+1)/a
= [2+a(a+1)(a+2)]/a
= 2/a + (a+1)(a+2)
= 2/(√3+1) + (√3+2)(√3+3)
= (√3-1) + 9 + 5√3
= 8+6√3