=1,a=2,原式=1/1*2+1/2*3+...+1/2009*2010=(1-1/2)+(1/2-1/3)+...+(1/2009-1/2010)=1-1/2010=2009/2010.
如果有理数a,b满足|ab-2|+|1-b|=0.试求1/ab+1/(a+1)(b+1)+1(a+2)(b+2)+…+1
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