Question

已经知道函数F(X)=IN（X+根号下X^2+1）,若实数A,B满足F(A)+F(B-2)=0,则A+B=?

Answer 1

∵f(-x)+f(x)=ln(-x+√(X^2+1)+ln(x+√(x^2+1) =ln(x^2+1-x^2) =ln1 =0 ∴f(x)是奇函数,这是-x+x=0 ∵F(A)+F(B-2)=0 ∴A+(B-2)=0即A+B=2