三角函数的综合题已知函数f(X)=cos^2x,g(x)=1+1/2sin2x1)若点A(α,y)(α∈[0,π/4])

2个回答

  • 1)联立y=cos²α,y=1+1/2sin2α,消去y有:

    cos²α=1+1/2sin2α

    (1+cos2α)/2=1+1/2sin2α

    1+cos2α=2+sin2α

    cos2α-sin2α=1

    cos2αcosπ/4-sin2αsinπ/4=√2/2

    cos(2α+π/4)=√2/2

    又α∈[0,π/4],2α+π/4∈[π/4,3π/4]

    ∴2α+π/4=π/4

    α=0

    2)

    f(x)=cos²x=(1+cos2x)/2

    y=cosx的对称轴为:y=kπ,k∈Z,

    ∴f(x)的对称轴为:2x=kπ,x=kπ/2,k∈Z

    g(2x)=g(kπ)=1+1/2sin2kπ=1

    3)

    h(x)=f(x)+g(x)=cos²x+1/2sin2x=(1+cos2x)/2 +1/2sin2x

    =(cos2x+sin2x)/2 +1/2

    =(sinπ/4cos2x+cosπ/4sin2x)√2/2+1/2

    =(√2/2)sin(2x+π/4)+1/2

    又x∈[0,π/4],2x+π/4∈[0,3π/4],

    ∴sin(2x+π/4)∈[√2/2,1]

    ∴ √2/2 *√2/2+ 1/2≤h(x)≤√2/2*1 +1/2

    h(x)的值域为:[1,(√2+1)/2]