计算题:1' (0.25)^-0.5+(1/27)^-(1/3)-625^0.25

1个回答

  • 1' (0.25)^-0.5+(1/27)^-(1/3)-625^0.25

    =(0.5)^-1+(1/3)^-1-5

    =2+3-5

    =0

    2' a^15 ×a^(-15) ×(a^-5)^0.5 ×(a^0.5)^3 (a>0)

    =a^0 ×(a^0.5 )^-5×(a^0.5)^3

    =(a^0.5 )^-2

    =a^-1

    =1/a

    3' (0.064)^-(1/3) -(-7/8)^0 +[(-2)^3]^(-4/3)+16^-0.75

    =0.4^-1 - 1 + (-2)^-4 + 2^-3

    =5/2-1+1/16+1/8

    =27/16

    4’(124+22√3 )^(1/2)-27^(1/6)+16^(3/4)-2×(8^-2/3)^- 1 +5√2 ×(4^-2/3)^-1

    因为11*11*3=121*3

    所以(124+22√3 )^(1/2)=11+√3

    原式=11+√3-√3+8-8+5√2*4^2/3

    =11+5√2*4^2/3