有一块长6m、重80N的均质木板通过中心放在锯木架上且保持两端自然平衡,现在该本板左端加放160N的重物,请问：如果想保持木板平衡,则该木板需要向右侧挪动多少距离?
设应挪动距离为x m
则依据杠杆平衡条件,即两边力与力臂乘积相等
即(160+40) X (3-x)=40 X (3+x)
x=2
因此,应挪动2mm,选B
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A uniform plank is 6.0 m long and weighs 80 N.It is balanced
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