最大值=3 最小值=-1
最大值=A+b,最小值=-A+b b=1 A=2
12/5π-(-12/π)=T/2 T/2=π/2 T=π T=2π /w w=2
则 f(x)=2sin(2x+φ)+1 代点M(3,12/5π)入f(x),可得到sin(5π/6+φ)=1 φ= -π/3
f(x)=2sin(2x-π/3)+1
f(x) 在[-π/3,-π/12] ……减
在[-π/12,5π/12] ……增
在[5π/12,2π/3] ……减
3.f(α)=2sin(2α-π/3)+1=2
sin(2α-π/3)=1/2 α∈(0,π),2α-π/3∈(-π/3,5π/3),
2α-π/3=π/6 α=π/4
2α-π/3=5π/6 α=7π/12
OK了