Question

证明:(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)

Answer 1

∵(tana-sina)(tana+sina)=sin^4a/cos²a

(tanasina)(tanasina)=sin^4a/cosa²a

∴(tana-sina)(tana+sina)=(tanasina)(tanasina)

∴(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)