Question

证明tanα+secα=tan(α/2+π/4)

Answer 1

tanα=2tan(α/2)/[1-tan(α/2)*tan(α/2)]secα=[1+tan(α/2)*tan(α/2)]/[1-tan(α/2)*tan(α/2)]tanα+secα=2tan(α/2)/[1-tan(α/2)*tan(α/2)]+[1+tan(α/2)*tan(α/2)]/[1-tan(α/2)*tan(α/2)]=[1+2tan(α/2...