f(x)=-f(-x)
f(-2x^2+3x)=-f[-(-2x^2+3x)]=-f(2x^2-3x)]
-f(2x^2-3x)+f(m-x-x^2)＞0
f(m-x-x^2)＞f(2x^2-3x)
f'(x)=[a^x+a^(-x)]lna
当a＞1时,f'(x)＞0,f(x)单调递增,
m-x-x^2＞2x^2-3x
3x^2-2x-m＜0
0≤x＜1/3+(1/3)√(1+3m)≤1
0≤1+3m≤4
-1/3≤m≤1
当a＜1时,f'(x)＜0,f(x)单调递减,
m-x-x^2＜2x^2-3x
3x^2-2x-m＞0
1/3+(1/3)√(1+3m)＜x≤1或0≤x＜1/3-(1/3)√(1+3m)≤1