Question

三角函数最大值最小值的题f(x)=sin(2x-π/6) 在区间[-π/6,5π/6]上的最大值和最小值 分别是 1 和

Answer 1

x belongs to [-pai/6,5pai/6],

so

2x-pai/6 belongs to [-pai/2,3pai/2]

draw the picture of this function

according to the picture,we can get that

f(x) belongs to [-1,1],

so

the maximum of the function is 1

the minimun of the function is -1

so

your answer is right