Question

已知x,y为实数,根号下3x+5与y平方的和-8y+16=0,若axy-6x=y,求a

Answer 1

x,y为实数,√(3x+5)+y^2-8y+16=0,

∴√(3x+5)+(y-4)^2=0,

∴3x+5=0,y-4=0,

∴x=-5/3,y=4,

由axy-6x=y得-20a/3+10=4,

解得a=0.9.