∵（x+2分之x+3）=（根号3）+（根号2）+1分之1
∴1+1/(x+2)=1/(√3+√2+1)
1/(x+2)=-(√3+√2)/(√3+√2+1)
x+2=-1-1/(√3+√2)=-1-√3+√2
x-2=-5-√3+√2
(x-2)²=25+3+2+10√3-10√2-2√6=30+10√3-10√2-2√6
∴原式=[（x-3)/[(x-3)/(2x-4)]/5/(x-2)-(x-2)]
=[(x-3)*(2x-4)/(x-3)]/[(5-x²+4x-4)/(x-2)]
=（2x-4)/(1-x²-4x)/(x-2)]
=2(x-2)²/[5-(x-2)²]
好麻烦.题目对不对?