已知弧长C=12.153M,弦长L=12.011M,求圆心角A是多少弧度!弧高H是多少?
弧半径为R.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=23
R1=22.908
R2=22.909
R3=22.909
R=22.909M
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((12.011/2)/22.909)
=30.395度
=30.395*PI/180
=0.53049弧度
H=R-R*COS(A/2)
=22.909-22.909*COS(30.395/2)
=0.801M