Question

两个计算题!1.[（3x+1）^2][(3x-1)^2]2.(x+1)[(x^2)+1][(x^4)+1](x-1)

Answer 1

1.[(3x+1)^2][(3x-1)^2]

=[(3x+1)(3x-1)]^2

=[9x^2-1]^2

=81x^4-18x^2+1

2.(x+1)[(x^2)+1][(x^4)+1](x-1)

=(x+1)(x-1)[(x^2)+1][(x^4)+1]

=(x^2-1)[(x^2)+1][(x^4)+1]

=[(x^4)-1][(x^4)+1]

=[(x^8)-1]