换底公式
原式=(lg3/lg4+lg3/lg8)*(lg2/lg3)
=(lg3/2lg2+lg3/3lg2)*(lg2/lg3)
=(lg3/2lg2)*(lg2/lg3)+(lg3/3lg2)*(lg2/lg3)
约分
=1/2+1/3
=5/6
[log4(3)+log8(3)]*log3(2)答案是1/3么
1个回答
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