设甲桶油X千克,甲桶比乙桶多1千克,则乙桶油（X-1）千克,
从甲桶里倒出7分之5千克到乙桶中,则甲桶油（X-5/7）千克,乙桶油（X-1+5/7）千克
（X-5/7）-（X-1+5/7）=-3/7
乙桶多,多3/7千克
(7.5/1+5/1)+5/1(x-1)=1 80/xX2+80/x+5 x8=4/3
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