Question

mx(m-x)-mn^2=n(n^2-x^2) 这题该怎么化成ax^2+bx+c=0的形式?当a=0时怎么解答?

Answer 1

mx(m-x)-mn^2=n(n^2-x^2)

m^2*x-mx^2-mn^2=n^3-n*x^2

n*x^2-mx^2+m^2*x-mn^2-n^3-=0

(n-m)x^2+m^2*x-(mn^2+n^3)=0

a=(n-m)

b=m^2

c=-(mn^2+n^3)

当a= 0时 a=n-m=0 n=m

b=m^2

c=-2m^3

所以(n-m)x^2+m^2*x-(mn^2+n^3)=0

变为m^2x-2m^3=0

m^2x=2m^3

x=2m=2n