x的n+3次方-x的n-1次方怎么解

1个回答

x的n+3次方-x的n-1次方
=x^(n+3)-x^(n-1)
=x^(n-1)(x^4-1)
=x^(n-1)(x^2-1)(x^2+1)
=x^(n-1)(x-1)(x+1)(x^2+1)