x1² + x1³ = 4 - (x2² + x2³)
x1² + x2² + x1³ + x2³ = 4
(x1 + x2)² - 2x1x2 + (x1 + x2)[(x1 + x2)² - 3x1x2] = 4
4p² + 2(3p + 2) + (-2p)[4p² + 3(3p+2)] = 4
p(4p + 3)(p + 1) = 0
△ = 4p² + 4(3p + 2) > 0
(p + 1)(p + 2) > 0
p = 0 或 p = -3/4
x1² + x1³ = 4 - (x2² + x2³)
x1² + x2² + x1³ + x2³ = 4
(x1 + x2)² - 2x1x2 + (x1 + x2)[(x1 + x2)² - 3x1x2] = 4
4p² + 2(3p + 2) + (-2p)[4p² + 3(3p+2)] = 4
p(4p + 3)(p + 1) = 0
△ = 4p² + 4(3p + 2) > 0
(p + 1)(p + 2) > 0
p = 0 或 p = -3/4