sin60°cos(-45)-sin(-420)cos(-570)
3个回答
=sin60cos45-sin(-360-60)cos(150-720)
=sin60cos45+sin60cos150
=√3/2×√2/2+√3/2×(-√3/2)
=(√6-3)/4
相关问题
求值[tan(-330)cos(-570)cos150sin(-420)]/[cos(-420)sin(-690)]
下列各三角函数值中:①sin(-600°) ②cos(-710°) ③tan255° ④sin420°cos570°
sin²60°+cos²60°、tan45°-sin30°×cos60°、cos²45°/
sin30° sin45° sin60° cos30° cos45° cos60° 以此类推,都等于多少
cos30°— sin45° ———————— sin60°— cos45°计算
计算:(sin60°−cos45°)(cos30°+sin45°)cos245°+cot60°•sin60°-3cot6
(cos(-570°)cos120°sin315°)/sin(-1050°)=?
(1+Cos45°-Sin30°)(1-Sin45°+Cos60°)=
sin45°×cos60°+sin45°
1.cos30°-sin45°/sin60°-cos45° 2.(sin30^2)30°+2sin60°+tha45°-