1) z= 5/(2-i)=5(2+i)/(2-i)(2+i)=5(2+i)/5=2+i
|z|=根号2^2+1^2=根号5
2)z=1+[5/(2-i)]=1+2+i=3+i
|z|=根号3^2+1^2=根号10