由于m^2=1-m
故m^5=m(1-m)^2
=m(m^2-2m+1)
=m(2-3m)
=2m-3m^2
=2m-3(1-m)
=5m-3
故m^5+2m+2008=7m+2005
而解m^2+m-1=0可得:m=(-1±√5)/2
所以7m+2005=4003/2±(7√5)/2.
若m^2+m-1=0,求m^5+2m^+2008的值.
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