(4x-y-1)^2+根号x+y-2=0得：4x-y-1=0与x+y-2=0解方程得x=3/5,y=7/5,4x^2y-4xy+xy^2=xy（4X-4+y）=21/25（-8/5+7/5）=-21/125
已知(4x-y-1)^2+根号x+y-2=0,求4x^2y-4xy+xy^2
2个回答
相关问题
-
已知（2x-y-1)^2+根号(xy-2)=0,求4x^3y-4x^2y^2+xy^3
-
已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2+xy^2的值.
-
已知（4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
-
初中数学已知(4x-2y-1)+根号xy-2=0,求4x^2y-4x^2y^2+xy^2的值
-
已知x^2+4y^2-4x+4y+5=0,求(x^4-y^4/2x^2+xy-y^2)*(2x-y/xy-y^2)/(x
-
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/x
-
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/x
-
已知｜x‐1｜+（y-1）²＝0 .求代数式（x²＋4xy－2y²）－（x²＋y）－2（y²＋xy
-
已知x^2+4y^2-2x+4y+2=0求（xy-x^2)/(x^2-2xy+y^2)/xy的值
-
已知2x+y=0,求x-2y/x²+xy乘(x²-y²)÷x²-4xy+4y