Question

这几个数学题怎么解1.已知方程x^2-(2i-1)x+3m-i=0有实根求实数m的解 ,2.解不等式Ix-8I-Ix-4

Answer 1

(1)x属于R

x^2-(2i-1)x+3m-i=0

(x^2+x+3m)-(2x+1)i=0

2x+1=0

x=-1/2

x^2+x+3m=0

1/4-1/2+3m=0

m=1/12

2 .X