(1)x属于R
x^2-(2i-1)x+3m-i=0
(x^2+x+3m)-(2x+1)i=0
2x+1=0
x=-1/2
x^2+x+3m=0
1/4-1/2+3m=0
m=1/12
2 .X
这几个数学题怎么解1.已知方程x^2-(2i-1)x+3m-i=0有实根求实数m的解 ,2.解不等式Ix-8I-Ix-4
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(1)x属于R
x^2-(2i-1)x+3m-i=0
(x^2+x+3m)-(2x+1)i=0
2x+1=0
x=-1/2
x^2+x+3m=0
1/4-1/2+3m=0
m=1/12
2 .X