令x²-x-12=0,则x=-3或x=4.所以-30,所以x1,即x∈(-无穷,-5/2)∪（1,+无穷）,
x²-x-120 x²+4x-12>0 -x²-2x+15≥0 2x²+3x-5
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1）4x2-12x-1=0 （2）3x2+2x-3=0 （3）5x2-4x-12=0 （4）3x(x+2)=5(x+2)
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(x1-x2+4x3-2x4=0;x1-x2-x3+2x4=0;3x1+x2+7x3-2x4=0;x1-3x2-12x3